Tuesday, August 21, 2012

Problem of the Week Day 2: Week of 8/20/12 - 8/24/12

Today is day 2 of the problem of the week. Remember to use yesterday's answers in today's problem.

Easy: For this problem, you will need to bring up yesterday's problem as well. Look at the matrix from yesterday and find the highest number there. Let's call that number g.

g =

Now, find the second highest number in the matrix. Let's call that number s.

s =

Finally, find the average of all of the numbers in the matrix. Round that to the nearest hundredth. That number will be called m.

m =

Now that we have those, we can begin the problem. Take a right triangle with the following side lengths. All of the measurements are in millimeters.

a = sgm + x
b = ___
c = y

Try to determine the length of b.

b =

Hard: This problem is trigonometric, but is also a real world problem. For my science fair experiment in 2011, I had to solve almost the same exact problem and it was actually really cool to see the real world application of trigonometry. I hope you find the applications of trigonometry as cool as I did while you complete this word problem. Before you begin, complete these two calculations:

f = x + (a + b)/(y + z)
f =

g = x + a + b
g =

Now for the fun part. Say you need to create a wooden ramp that is f meters long and is propped at an a° angle. You will prop it up with another piece of wood g centimeters up from the bottom and you want the support to make it an a° angle ramp. How many centimeters long should your support be to achieve this angle? Round to the nearest centimeter.

s =

Good luck, and remember to save your answers for tomorrow.

1 comment:

  1. Math comes with more tricks and styles to solve a single problem some time we use these tricks for making puzzles and to discover new simple methods. Maths tricks like these type are more liked by me as they are quite refreshing and good.