I have discussed a few other methods of multiplication on this blog, one of which is the Criss-Cross Method. Again, I won't explain it here, but this method does lay the foundation for the new method I am going to explain today.

Rather than taking you through the steps, I will post a video tutorial on how to do it (those are usually more fun anyways). If you are wondering why it works, I encourage you to refer back to the Criss-Cross Method and notice the similarities. Try a few problems with the Criss-Cross Method, and then this method, and see how the numbers that appear throughout the problem seem to be identical.

When you watch this video, I would strongly suggest doing the examples along with the video. It can be a very useful technique for problems whose digits are of a reasonable size.

I think this is a really cool method of multiplication, and even easier to teach than the traditional method. Play around with it, and you will likely end up using it in the future.

For some more intellectual readers, it might be fun to try multiplying numbers with bigger digits using the quinary or senary number systems (base five or base six). This would make less dots in each section. I think it might be a fun exercise.

Answers to June Problem of the Week:

*For the answers to the creation of a line of best fit, it will be written as an inequality. There is no way to get the exact answer by hand, so just make sure your answer is in the interval that is written.

Easy:

*a*= 7

^{1}/

_{3}

*p*= 14

*m*=

^{118988}/

_{6925}

*n*=

^{394}/

_{277}

*y*= 15.76

*z*= 12.08

*g*= 8

*b*= 112

*q*= 44

*x*= 33

Medium:

*h*= 105

*p*= 270

*t*= 19

*n*= 92925

*u*= 92.925

*q*= 135

*a*= 2165.2875

*d*= 21.652875

*g*= 15

*j*= 46.4625

*k*= 23.23125

*r*= 27

*s*= 45

2 <

*m*< 3.5

45 <

*b*< 50

175 <

*x*< 275

Hard:

*s*= 107

*t*= 365

*p*= 905

*q*= 4096

*q*

_{0}= 4096

*q*

_{1}= 2048

*q*

_{2}= 1024

*q*

_{3}= 512

*q*

_{4}= 256

*q*

_{5}= 128

*q*

_{6}= 64

*q*

_{7}= 32

*q*

_{8}= 16

*q*

_{9}= 8

*q*

_{10}= 4

*q*

_{11}= 2

*q*

_{12}= 1

*q*

_{13}=

^{1}/

_{2}

*q*

_{14}=

^{1}/

_{4}

*q*

_{15}=

^{1}/

_{8}

*x*

_{1}= -452.5

*x*

_{2}= -2

*x*

_{3}= 4

*y*= 0

*a*= 226.25

*b*= -224.25

*c*= -454.5

*t*= 2635773.77

*m*= 34

*x*= 79.53%

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