Problem of the Week Day 5: Week of 7/15/13 - 7/19/13

Today is the final day of the problem of the week. In all three problems, your goal is to find the value of x. Good luck!

Easy:

Find the mean of the following list of numbers:

a

b

f

g

q

x = ____

Medium:

The data set below represents the test scores of nine students based on the amount of absences they had.

x	y
f - f1 - f2 - f3 - f4	ceiling(n ÷ f - r)
floor(f4 - f2 - r)	floor(8r)
floor(f2 ÷ f3)	ceiling(2f4 - r)
3√(f1 - f4)	f ÷ 2
ceiling(f2 - f3 - r)	2f2
√(f3)	floor(f1 - r)
floor(n ÷ 1000)	floor(n ÷ 100)
f1 - f4	f1
f4 - f2	f4

Find the line of best fit for this data set. It should be of the form y = mx + b.

m = ____

b = ____

Now, find the predicted score of a student with ten absences.

x = ____

Hard:

Take the following matrix that represents the payoffs in a mathematical game.

	A	B
1	b, w - 6	s, -t
2	-b, a	-a, c
3	-g, -d	-f, b

After eliminating any dominated strategies, use mixed strategy Nash equilibria to determine the percent of the time that strategy 1 should be played.

x = ____

The answers to the problem will be up in a month. I will post the answers to June’s problem of the week with tomorrow's post.