Today is the final day of the problem of the week. In all three problems, your goal is to find the value of x. Good luck!
Easy:
Find the mean of the following list of numbers:
a
b
f
g
q
x = ____
Medium:
The data set below represents the test scores of nine students based on the amount of absences they had.
x

y

f  f_{1 } f_{2}  f_{3}  f_{4}

ceiling(n ÷ f  r)

floor(f_{4 } f_{2 } r)

floor(8r)

floor(f_{2 }÷ f_{3})

ceiling(2f_{4 } r)

^{3}√(f_{1 } f_{4})

f ÷ 2

ceiling(f_{2 } f_{3 } r)

2f_{2}

√(f_{3})

floor(f_{1 } r)

floor(n ÷ 1000)

floor(n ÷ 100)

f_{1 } f_{4}

f_{1}

f_{4 } f_{2}

f_{4}

Find the line of best fit for this data set. It should be of the form y = mx + b.
m = ____
b = ____
Now, find the predicted score of a student with ten absences.
x = ____
Hard:
Take the following matrix that represents the payoffs in a mathematical game.

A

B

1

b, w  6

s, t

2

b, a

a, c

3

g, d

f, b

After eliminating any dominated strategies, use mixed strategy Nash equilibria to determine the percent of the time that strategy 1 should be played.
x = ____
The answers to the problem will be up in a month. I will post the answers to June’s problem of the week with tomorrow's post.
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